|
where N equals the number of differences (100 in this case), is the arithmetic mean and SD is the standard deviation. We next calculate the critical value as T = KSD + | | where K = 1.87, based on 100 samples. (d) Equivalency test. The next step is to obtain the average of the 100 VE readings. This is obtained by equation (4)
We next multiply 0.25 by VE. If T < 0.25 VE, we can say that the alternate device has passed the equivalency test. [Statutory Authority: RCW
49.17.040 and
49.17.050. WSR 86-16-009 (Order 86-28), § 296-62-14543, filed 7/25/86.]